You push down on the car to provide more friction for the tires allowing the cars tires to propel it forward 5 meters. how much work do you do?

The work done by you, W = 9800 J

Explanation:

Given data,

The displacement of the car, S = 5 m

Let the mass of the car be, m = 2000 kg

Let the coefficient of static friction be 0

Hence, no frictional force is acting on the tire and ground.

Let, you push down the car to provide more friction, μₓ = 0.1 (you can change the value)

In order to provide the static friction, you push down the car is equal to the static friction force,

                                      Fₓ =  μₓ · η

Where,

                                 η - normal force acting on the car (mg)

Substituting the values,

                                   Fₓ = 0.1 x 2000 x 9.8

                                       = 1960 N  

Therefore work done,

                                   W = Fₓ x S

                                        = 1960 N x 5 m

                                        = 9800 J

Hence, the work done by you, W = 9800 J

answer: the correct answer id option(d).

explanation:

snell's law refraction:

the angle of refraction =

the angle of incidence =

refractive index of air = = 1

refractive index of glycerol = 1.47

from the given options, the most closest answer to 63.72° is 65° of option (d).

answer: the correct answer is   air pressure at the top of mount everest is higher than at the bottom of the grand canyon.

hope this : )

explanation: