You charge a parallel-plate capacitor, remove it from the battery, and prevent the wires connected to the plates from touching each other. when you pull the plates apart to a larger separation, do the following quantities increase, decrease or stay the same? i) cii) qiii) e between the platesiv) delta v

i) C decreases

ii) Q remains constant

iii) E remains constant

iv) ΔV increases

Explanation:

i)

We know, capacitance is given by:

In this case as the distance between the plates increases the capacitance decreases while area and permittivity of free space remains constant.

ii)

As the amount of charge has nothing to do with the plate separation in case of an open circuit hence the charge Q remains constant.

iii)

Electric field between the plates is given as:

where:

charge density,

As we know that distance of plate separation cannot affect area of the plate. Charge Q and permittivity are also not affected by it, so E remains constant.

iv)

pe = weightxheight = 2000x1000=2,000,000joules

gpe = mass x gravity constant x height or… gpe = mgh

where… mass: measured in kilograms (kg)

gravity: gravity constant on earth = 10.00 m/s2

height: measured in meters (m)

gpe: measured in joules (j) or kilojoules (kj)

how do you solve gpe?

gravitational potential energy (gpe) is the energy an object has because of its position above the. ground.

gpe = mass x gravity constant x height or… gpe = mgh.

mass:

note: to earn full marks when solving science word problems, you must show your work:

formula.

example:

given values:

mass = 0.3 kg.