Fr = 12 cm, m = 360 g, and m = 70 g (below), find the speed of the block after it has descended 50 cm starting from rest. solve the problem using energy conservation principles. (treat the pulley as a uniform disk.) solve the problem using energy conservation principles. (b) repeat (a) with r = 5.0 cm.

The speed of the block is 1.65 m/s.

Explanation:

Given that,

Radius = 12 cm

Mass  of pulley= 360 g

Mass of block = 70 g

Distance = 50 cm

(a). We need to calculate the speed

Using energy conservation

Put the value into the formula

(b), We need to calculate the  speed of the block

When r = 5.0 cm

Here, The speed of the block is independent of radius of pulley.

Hence, The speed of the block is 1.65 m/s.

the answer is a 3.8cm

explanation:

the motion of a pendulum is a classic example of mechanical energy conservation. a pendulum consists of a mass (known as a bob ) attached by a string to a pivot point. as the pendulum moves it sweeps out a circular arc, moving back and forth in a periodic fashion.