Aheater 0.015 m in diameter and 0.3 m long is submerged horizontally in oil at 20 oc. to avoid oil fumes, the heater surface should not exceed ts= 150 oc. calculate the maximum power that should be supplied to the heater.

The maximum power is 23.89 k watt.

Explanation:

Given that,

Diameter = 0.015 m

Long = 0.3 m

Initial temperature = 20°C

Final temperature = 150°C

Suppose the material is copper and here no maintain at time so we assuming heat supplied per unit time

We need to calculate the energy

Using formula of energy

We need to calculate the power

Using formula of power

Hence, The maximum power is 23.89 k watt.

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