A0.150 kg toy is undergoing shm on the end of a horizontal spring with force constant 300.0 n/m. when the object is 0.0120 m from its equilibrium position, it is observed to have a speed of 0.200 m/s. find(a) the total energy of the object at any point in its motion,(b) the amplitude of the motion, and(c) the maximum speed attained by the object during its motion.

a)TE=0.0245 J

b)A = 0.0128 m

c)V=0.57 m/s

Explanation:

Given that

m = 0.150 kg

K= 300 N/m

x= 0.012 ,v= 0.2 m/s

The velocity of the toy at any point given as

2 x 10⁻⁵ = A² - 0.000144

A=0.0128 m

Amplitude ,A = 0.0128 m

The total energy TE

TE=0.0245 J

The maximum speed

V=0.57 m/s

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