Acubical box 25.0 cm on each side is fully immersed in a fluid. the pressure at the top surface of the box is 109.40 kpa and the pressure on the bottom surface is 112.00 kpa. what is the density of the fluid?

ρ = 1061 kg/m³

Explanation:

The pressure at the top pf the box is clearly different from the pressure at the bottom of of the  box due to the depth. So the problem can be solve the following way:

Difference in pressure =  density * acceleration due to gravity * height

ΔP = ρgΔh

112 000 Pa - 109 400 Pa = ρ * 9.8 m/s² * 0.25 m

                                     ρ = 1061 kg/m³

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j