A0.026 kg bullet is fired straight up at a falling wooden block that has a mass of 5.0 kg. the bullet has a speed of 750 m/s when it strikes the block. the block originally was dropped from rest from the top of a building and had been falling for a time t when the collision with the bullet occured. as a result of the collision, the block (with the bullet in it) reverses direction, rises, and comes to a momentary halt at the top of the building. find the time t.

0.198 s

Explanation:

Consider the motion of the block  before collision

= initial velocity of block as it is dropped = 0 m/s

= acceleration = - g

= time of travel

= final velocity of block before collision

Using the kinematics equation

= mass of the bullet = 0.026 kg

= velocity of block just before collision = 750 m/s

= mass of the block = 5 kg

= final velocity of bullet block after collision = gt

Using conservation of momentum

well, you would divide 135 by 33 to get your answer. then that is how many seconds it would take. boardman should fly about 132 m or 4.090909090909091 seconds.

r = ρ x length / area  

ρ = r x area / length  

ρ is in ohm-meters  

in basic units, it is m³kg/s³a²  

i think this is it.