The end point of a spring vibrates with a period of 2.1 seconds when a mass m is attached to it. when this mass is increased by 6.810×101 kg, the period is found to be 3.4 seconds. find the value of m.

Mass attached to the spring is 41.95 kg

Explanation:

We have given time period of the spring T = 2.1 sec

Let the mass attached is m

And spring constant is k

We know that time period is given by

---------eqn 1

Now if the mass is increased by 68.10 kg then time period become 3.4 sec

So ------eqn 2

Now dividing eqn 1 by eqn 2

So mass attached to the spring is 41.95 kg

f=ma a/f/m a= 480/60 a = 8m/s/s that is quick wow

measuring things 1 litre of water