Acar traveling 6.0 m/s is uninformly accelerating at a rate of 3.0 m/s^2 for 15 seconds. what is it’s final velocity?

The answer to your question is 11.2 m/s

Explanation:

Data

Initial speed (vo) = 6.0 m/s

Acceleration (a) = 3.0 m/s²

time = 15 s

Final speed = ?

Formula

                d = vot +

                vf² = vo² + 2ad

Process

                d = (6)(15) +

                d = 90 + 337.5

                d = 427.5 m

                vf² = (6)² + 2(3)(15)

                vf² = 36 + 90

                vf² = 126

                vf = 11.2 m/s

answer: b.

explanation:

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west