You (50 kg) are standing on a floating log (200 kg). both are floating down a river at 1 m/s. the log points in the direction along the river. you walk in a direction that is down river for 5 seconds and your speed is 1.5 m/s as measured by a ground observer at the end of the 5 seconds.
a. what is the speed of the log at the end of the 5 seconds?
b. what is the average force between you and the log during those 5 seconds?

0.875 m/s

5 N

Explanation:

= Mass of person = 50 kg

= Mass of log = 200 kg

= Velocity of person = 1.5 m/s

= Velocity of log

v = Velocity of log with respect to shore = 1 m/s

t = Time taken = 5 seconds

As the momentum of system is conserved we have

Velocity of the log at the end of the 5 seconds is 0.875 m/s

Force is given by

The average force between you and the log during those 5 seconds is 5 N

explanation:

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explanation: