Biconvex" lens is one in which both surfaces of the lens bulge outwards. suppose you had a biconvex lens with radii of curvature with magnitudes of |r1|=10cm and |r2|=15cm. the lens is made of glass with index of refraction nglass=1.5. we will employ the convention that r1 refers to the radius of curvature of the surface through which light will enter the lens, and r2 refers to the radius of curvature of the surface from which light will exit the lens.
part a is this lens converging or diverging?
a. converging
b. diverging
part b what is the focal length f of this lens in air (index of refraction for air is nair=1)? express your answer in centimeters to two significant figures or as a fraction. view available hint(s) ff f = nothing cm
part c complete previous part(s).

    m₁v₁ + m₂v₂ = (m₁ + m₂)vmomentum is conserved.the left-hand side of the equation represents the momentum in the system before the collision.the right-hand side represents the momentum in the system after the collisionm₁ and v₁ represents the mass and the velocity of the physics blockm₂ and v₂ represents the mass and velocity of the ball of puttyv represents the final velocity of the combined mass.the question states the two masses stick together. they combined mass has its own velocity with the body mass the sum of the two objects' massestheir combined momentum is (m₁ + m₂)vto find the magitude of (m₁ + m₂)v, we need to add the vectors on the left-hand side of the equation: m₁v₁ + m₂v₂.note the diagram. i have positioned the vectors in accordance with their directions.the magnitude of the resultant can be calculated using the pythagorean theorem since this is a right triangle situation (north and west are perpendicular)|(m₁ + m₂)v| =  √[ (m₁v₁)² + (m₂v₂)² ]|(m₁ + m₂)v| =  √[ (1.5kg·8.0m/s)² + (0.40kg·20m/s)² ]|(m₁ + m₂)v| =  14.4 kg m/sfor two significant figures (assuming that 20m/s is two), this rounds to 14 kg m/s

Answerapply an acl that has all deny ace statement;

Answer(b) both involve the use of levers;