4. the bar has cross-sectional area a and modulus of elasticity e. if an axial force f directed toward the right is applied at c: (a) what is the normal stress in the part of the bar to the left of c? [15 pts] (b) what is the resulting displacement of the point c? [15 pts]

a)  ΔL/L = F / (E A),  b)   = L (1 + L F /(EA) )

Explanation:

Let's write the formula for Young's module

     E = P / (ΔL / L)

Let's rewrite the formula, to have the pressure alone

    P = E ΔL / L

The pressure is defined as

    P = F / A

Let's replace

   F / A = E ΔL / L

   F = E A ΔL / L

   ΔL / L = F / (E A)

b) To calculate the elongation we must have the variation of the length, so the length of the bar must be a fact. Let's clear

    ΔL = L [F / EA]

    -L = L (F / EA)

    = L + L (F / EA)

    = L (1 + L (F / EA))

e

explanation:

there is no change in the electric potential energy as it is in rest on both conditions.