Abucket of water of mass 14.7 is suspended by a rope wrapped around a windlass, that is a solid cylinder with diameter 0.280m with mass 11.6 kg. the cylinder pivots on a frictionless axle through its center. the bucket is released from rest at the top of a well and falls a distance 10.3m to the water. you can ignore the weight of the rope.

part a
what is the tension in the rope while the bucket is falling
-take the free fall acceleration to be g=9.80 m/s squared

part b
with what speed does the bucket strike the water?
-take the free fall acceleration to be g=9.80 m/s^2

part c
what is the time of fall
-take the free fall acceleration to be g=9.80m/s^2

part d
while the bucket is falling, what is the force exerted on the cylinder by the axle?
-take the free fall acceleration to be g=9.80 m/s^2

Explanation:

Tension T in the rope will create torque in solid cylinder ( axle ). If α be angular acceleration

T R = 1/2 M R²α ( M is mass and R is radius of cylinder )

= 1/2 M R² x a / R ( a is linear acceleration )

T = Ma / 2

For downward motion of the bucket

mg - T = m a ( m is mass and a is linear acceleration of bucket downwards )

mg - Ma / 2  = ma

a = mg / ( M /2 + m )

Substituting the values

a = 14.7 x 9.8 / ( 5.8+ 14.7 )

= 7 m / s²

A )

T = Ma / 2

= 5.8 x 7

= 40.6 N

B ) v² = u² + 2 a h

= 2 x 7 x 10.3

v = 12 m /s

C )

v = u + a t

12 = 0 + 7 t

t = 1.7 s

the focus of lesson 1 is newton's first law of motion - sometimes referred to as the law of inertia. newton's first law of motion is often stated as. an object at rest stays at rest and an object in motion stays in motion with the same speed and in the same direction unless acted upon by an unbalanced force.

explanation:

what are the statements? x