Agolf club exerts and average force of 1000n on a 0.045-kg golf ball which is initially at rest. the club is in contact with the ball for 1.8ms. what is the speed of the golf ball it leaves the tee?
a batter applies an average force if 8000n to a baseball for 1.10ms. what is the magnitude of the impulse delivered to the baseball?

Explanation:

Given that,

Average force exerting on the golf club, F = 1000 N

Mass of the ball, m = 0.045 kg

Initial speed of the ball, u = 0

The time of contact between the ball and the club,

1. Let v is the speed of the golf ball as it leaves the tee. The product of force and time is equal to the change in its momentum as :

v = 40 m/s

2. Force applied by the batter, F = 8000 N

Time,

Let J is the magnitude of the impulse delivered to the baseball. It is equal to the product of force and time as :

J = 8.8 kg-m/s

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