An empty parallel plate capacitor is connected between the terminals of a 4.4-v battery and charged up. the capacitor is then disconnected from the battery, and the spacing between the capacitor plates is quadrupled. as a result of this change, what is the new voltage between the plates of the capacitor?
i have: e = v/de =9 vthen the distance is doubled 9(2) = 18 v
Answers: 3
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An empty parallel plate capacitor is connected between the terminals of a 4.4-v battery and charged...
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