In the 1950’s, an experimental train that had a mass of 36100 kg was powered across a level track by a jet engine that produced a thrust of 4.66 × 10⁵ n for a distance of 433 m. find the work done on the train.

202 MJ

Explanation:

Work done = force applied x distanced moved in the direction of the force

                      applied

                    = 4.66 x 10^5 N * 433 m

                    = 201 778 000 J

                     = 202 MJ

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west