An proton-antiproton pair is produced by a 2.20 × 10 3 mev photon. what is the kinetic energy of the antiproton if the kinetic energy of the proton is 242.85 mev? use the following joules-to-electron-volts conversion 1ev = 1.602 × 10-19 j. the rest mass of a proton is 1.67 × 10 − 27 kg.

K = 80.75 MeV    

Explanation:

To calculate the kinetic energy of the antiproton we need to use conservation of energy:

where : is the photon energy, : are the rest energies of the proton and the antiproton, respectively, equals to m₀c², : are the kinetic energies of the proton and the antiproton, respectively, c: speed of light, and m₀: rest mass.        

Therefore the kinetic energy of the antiproton is:    

The proton mass is equal to the antiproton mass, so:

Hence, the kinetic energy of the antiproton is 80.75 MeV.

I hope it helps you!

layer a is the exosphere and layer b is the thermosphere.   is the answer i think but i hope this .

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.