A240 g toy car is placed on a narrow 60-cm-diameter track with wheel grooves that keep the car going in a circle. the 1.0 kg track is free to turn on a frictionless, vertical axis. the spokes have negligible mass. after the car's switch is turned on, it soon reaches a steady speed of 0.79 m/s relative to the track. what then is the track's angular velocity, in rpm?

The track's angular velocity is W2 = 4.15 in rpm

Explanation:

Momentum angular can be find

I = m*r^2

P = I*W

So to use the conservation

P1 + P2 = 0

I1*W1 + I2*W2 = 0

Solve to w2 to find the angular velocity

0.240kg*0.30m^2*0.79m/s=-1kg*0.30m^2*W2

W2 = 0.435 rad/s

W2 = 4.15 rpm

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current and voltage can both be different in different parts of a circuit so it matters where you place the ammeter and voltmete