An 8.6 g bullet is fired into and embeds itself in a 1.48 kg block attached to a spring with a spring constant of 20.4 n/m and whose mass is negligible. how far is the spring compressed if the bullet has a speed of 123 m/s just before it strikes the block, and the block slides on a frictionless surface? answer in units of m.

To solve this problem it is necessary to apply the concepts concerning conservation of the linear momentum as well as the equations of energy acquisition for springs.

From the definition of conservation of linear momentum we have to,

Where,

Final velocity

Mass of the bullet

Mass of the block

Initial velocity of the bullet

initial velocity of the block

The block does not have initial speed because it is at rest, then replacing we have to,

Re-arrange to find

Now applying the energy conservation equations we have that the potential and kinetic energy of the spring must be maintained in the way

If the spring is compressed, then the velocity becomes zero. Here the kinetic energy is zero and the spring potential energy as follow,

Re-arrange to find x,

Therefore the spring is compressed around to 0.1913m

b.

explanation:

10.0

5 w for 1hr = 5x60x60 joules=300x60=3000x6=18,000j as total energy conversion. efficiency of bulb needed for radiant to thermal within 18000