The moment of inertia of the empty turntable is 1.5 kg? m2. with a constant torque of 2.5 n? m, the turntableperson system takes 3.0 s to spin from rest to an angular speed of 1.0 rad/s. what is the persons moment of inertia about an axis through her center of mass? ignore friction in the turntable axle.

the moment of inertia of the empty turntable is 1.5 . with a constant torque of 2.5 , the turntableperson system takes 3.0 to spin from rest to an angular speed of 1.0 . what is the persons moment of inertia about an axis through her center of mass? ignore friction in the turntable axle.

2.5 kg? m2
6.0 kg? m2
7.5 kg? m2
9.0 kg? m2

is the persons moment of inertia about an axis through her center of mass.

Option B

Explanation:

Given data are as follows:

moment of inertia of the empty turntable = 1.5

Torque = 2.5 N/m , and

Let the persons moment of inertia about an axis through her center of mass= I

So, Now, from the formula of torque,

So, from the above equation, we can measure the person’s moment of Inertia (I)

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the small 0.38-kg slider is known to move from position a to position b along the vertical-plane slot. determine (a) the work done on the body by its weight and (b) the work done on the body by the spring. the distance r = 0.70 m, the spring modulus k = 154 n/m, and the unstretched length of the spring is 0.53 m

explanation:

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