Two lifeguards pull on ropes attached to a raft. if they pull in the same direction, the raft experiences a net external force of 347 n to the right. if they pull in opposite directions, the raft experiences a net external force of 122 n to the left.
draw a free body diagramfor each situation and find the magnitude of the larger of the two individual forces.

F1 = 234.5

Explanation:

F1 = force applied by the first life guard

F2 = force applied by the second life guard

          F1 + F2 = 347  ...equation 1

             F1 - F2 = 122 ....equation 2

        (347 - F2) - F2 = 122

         347 - 2F2 = 122

           2F2 =347 - 122

            F2 = 225 ÷ 2 = 112.5 N

               F1 + F2 = 347

               F1 + 112.5 = 347

               F1 = 347 - 112.5 = 234.5 N

Therefore F1 = 234.5 and F2 = 112.5

     the larger of the two forces is F1 = 234.5

most voltage drop calculators want the distance between the source and destination. then internally, they double it so both the source and return wires are calculated. but you need to know which distance the calculator uses so you're not half of what you should be or double what you should be.

most circuit breakers will not take a #6 directly, so the electrician will have to splice on a smaller pigtail. you also have to upsize the grounding wire when you upsized the ungrounded (hot) wire (see note in 250.122). this will preclude using most cable assemblies, as a cable with #6 copper will most likely only have a #10 grounding conductor. you need a #6 grounding conductor if the circuit is 20a. a #8 cable is no better, as it will have a #10 grounding conductor too. but most 20a breakers will take a #8 directly.

in your related post, you didn't say what type of load this is. if it is a light or heater, voltage drop won't be a big issue. if this is a motor, the current needs are huge at startup and the voltage drop can pose a problem. if this is a motor, knowing if the motor is under much load during startup will answer the voltage drop effect (a saw is easier to start than a compressor).