Abrass ring of diameter 10.00 cm at 20.7°c is heated and slipped over an aluminum rod of diameter 10.01 cm at 20.7°c. assume the average coefficients of linear expansion are constant. (a) to what temperature must the combination be cooled to separate the two metals

Explanation:

Given:

We have:

(a)

Initial circumference of the brass ring:

Initial circumference of the aluminium rod:

According to condition:

The final circumference of the two must be at least equal to separate them.

Now, the final temperature:

is the temperature to which the combination must be cooled to separate the two metals.

the current is 0.6

voltage ÷ resistance = current

so 12 ÷ 20 = 0.6

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