Physics, 27.11.2019 01:31 kalo1023

The flowers of the bunchberry plant open with astonishing force and speed, causing the pollen grains to be ejected out of the flower in a mere 0.30 ms at and acceleration of 2.5×104m/s2. if the acceleration is constant, what impulse in 10−10kgm/s is delivered to a pollen of mass 1.0×10−7g? (do not include unit in answer)

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Answer from: chancecharles9oug353

$7.5(10)^{-10} kg m/s$

Explanation:

The impulse is given by:

p=mV (1)

Where:

$m=1(10)^{-7}g \frac{1 kg}{1000 g}=1(10)^{-10} kg$ is the mass of the pollen

is the velocity of the pollen

On the other hand, we know acceleration is:

$a=\frac{V}{t}$ (2)

Where $t=0.3 ms=0.3(10)^{-3} s$ is the time and $a=2.5(10)^{4}m/s^{2}$

Then: V=a.t (3)

Substituting (3) in (1):

p=m.a.t (4)

$p=(1(10)^{-10} kg)(2.5(10)^{4}m/s^{2})(0.3(10)^{-3} s)$ (5)

Finally:

$p=7.5(10)^{-10} kg m/s$

Answer from: BeeShyanne

Impulse : 7.5.10⁻¹⁰N.s

Further explanation

Momentum is the product of the mass of an object and its velocity

p = mv

Whereas impulse is defined is the product of the force with the time interval when the force is acting on the object.

I = F. Δt

the pollen grains to be ejected out of the flower in 0.30 ms and acceleration of 2.5 × 10⁴ m/s², then

Δt = 0.3 ms = 3.10⁻⁴ s

a = 2.5 × 10⁴ m/s²

mass of pollen: 1.0 × 10⁻⁷g = 1.0 x 10⁻¹⁰ kg

then:

A force that works according to Newton's second law:

F = m. a

$\rm F=1.0\times 10^{-10}\times 2.5\times 10^4\\\\F=2.5\times 10^{-6}\:N$

Impulse (I) :

$\rm I=2.5 \times 10^{-6}\times 3\times 10^{-4}\\\\I=7.5\times 10^{-10}N.s$

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Answer from: Quest

i had this question and the answer was 3.15 miles.

martina travels from school to her mom's office. from there, she walks to school. after school, she walks to the library and then to a friends house before finally ending back at home. find martina's total distance traveled.

a) 0 miles

b) 0.4 miles

c) 1 mile

d) 3.15 miles

Answer from: Quest

force is based upon mass and acceleration.the statement is not always true.

it can be explained from newton's second law of motion.

as per newton's second law of motion the rate of change of momentum is directly proportional to the applied force and takes place along the direction of force.

mathematically it can be written as -

$f\alpha \frac{dp}{dt}$

⇒ $f= k \frac{dp}{dt}$

here k is the proportionality constant whose value is 1.

$f=\frac{dp}{dt}$

$f= \frac{d[mv]}{dt}$

$f= m\frac{dv}{dt} +v\frac{dm}{dt}$

$f=ma+v\frac{dm}{dt}$ [a is the acceleration=dv/dt]

hence we see that force not only depends on mass and acceleration but also on velocity and rate of change of mass. force f will depend on mass and acceleration only when mass is constant.

hence the statement that force is based upon mass and acceleration is false.

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