A181-kg bookcase is at rest in the front office. a custodian pushes horizontally on the bookcase to try to move it. if it takes 584 n of force before the bookcase begins to move, find the coefficient of static friction between the bookcase and the floor.

The coefficient of static friction between the bookcase and the floor,  μₓ = 0.3292

Explanation:

Given data,

The mass of the bookcase, m = 181 kg

The static frictional force of the bookcase, Fₓ = 584 N

The gravitational normal force acting on the bookcase is, F = m g

                                                                                       = 181 x 9.8

                                                                                       = 1773.8 N

The formula for static frictional force is

                                         Fₓ = μₓ F

Where μₓ - the coefficient of the static friction

                                        μₓ = Fₓ / F

                                             = 584 N / 1773.8 N

                                             = 0.3292

Hence, the coefficient of static friction between the bookcase and the floor,  μₓ = 0.3292

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