Abat strikes a 0.145-kg baseball. just before impact, the ball is traveling horizontally to the right at and it leaves the bat traveling to the left at an angle of above horizontal with a speed of if the ball and bat are in contact for 1.75 ms, find the horizontal and vertical components of the average force on the ball.

Answer

given,

mass of the baseball = 0.145 Kg

Assuming the horizontal velocity of ball = V x = 50 m/s

ball left at an angle of = 30°

At the speed of 65 m/s

time of contact  = 1.75 ms

velocity of time along horizontal direction

v_{horizontal} = -65 cos 30° - 50

                        = -106.29 m/s

Impulse = force x time

impulse is equal to change in momentum

now,

force x time = m v

F_{horizontal} = - 8.806 kN

now velocity in vertical component

v_{vertical} = 65 sin 30°

                  = 32.5 m/s

F_{vertical} = 2.692 kN

b

explanation:

bc its just b