An empty capacitor is capable of storing 1.0 × 10-4 j of energy when connected to a certain battery. if the distance between the plates is halved and then filled with a dielectric (κ = 2.8), how much energy could this modified capacitor store when connected to the same battery?

Explanation:

d = Distance between capacitors

V = Voltage

k = Dielectric

A = Area

= Permittivity of free space

Energy the capacitor stores

Capacitance is given by

The new capacitance will be

New energy will be

The energy the modified capacitor store when connected to the same battery is

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i believe the answer is electric potential.

explanation: