Find α, the angular acceleration of the wheel, which results from f⃗ pulling the string to the left. use the standard convention that counterclockwise angular accelerations are positive. express the angular acceleration, α, in terms of f, r, m, and k (but not iw).

α = F/(k×m×r)

Explanation:

When the wheel is pulled to turn in a counterclockwise direction, the wheel will have a moment of inertia given by Iw = k×m×r²

Where k = the radius of gyration of the wheel which is a dimensionless quantity less than one.

m = the mass of the wheel

r = the radius of the wheel

First and foremost, we relate the torque (τ) about the axle of the wheel to the force (F) applied on the wheel and we have that τ = r × F

We then relate the torque on the wheel to the angular acceleration (α), we have that τ = Iw × α, where Iw is the moment of inertia of the wheel as explained above

Substituting for torque τ and moment of inertia I into the above equation we have that

r × F = k×m×r² × α

solving for α we have that

α = r × F /(k×m×r²)

Therefore

α = F/(k×m×r)

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explanation:

the body's situation won't change the forces are equal opposit and on the same body