A3.00-m rod is pivoted about its left end. a force of 7.80 n is applied perpendicular to the rod at a distance of 1.60 m from the pivot causing a ccw torque, and a force of 2.60 n is applied at the end of the rod 3.00 m from the pivot. the 2.60-n force is at an angle of 30.0o to the rod and causes a cw torque. what is the net torque about the pivot? (take ccw as positive.)

a. 26.4 n·m

b. 4.68 n·m

c. 8.58 n·m

d. -8.58 n·m

e. -16.4 n·m