In simple harmonic motion, the speed is greatest at that point in the cycle whena) the magnitude of the acceleration is a maximum. b) the displacement is a maximum. c) the magnitude of the acceleration is a minimum. d) the potential energy is a maximum. e) the kinetic energy is a minimum.

C) the magnitude of the acceleration is a minimum.

Explanation:

As we know that ,the general equation of the simple harmonic motion given as

The displacement x given as

x=X sinω t

Then the velocity v will become

v= X ω cosωt

The acceleration a

a= - X ω² sinω t

The speed of the particle will be maximum when cosωt will become 1 unit.

It means that sinωt will become zero.So acceleration and displacement will be minimum.

Therefore when speed is maximum then acceleration will be minimum.

At the mean position the speed of the particle is maximum that is why kinetic energy also will be maximum and the potential energy will be minimum.

Therefore option C is correct.

i would say the answer is food.

hope this !

double the distance = divide strength by 4