Aparticle is moving in simple harmonic motion with an amplitude of 3.0 cm and a maximum velocity of 15.0 cm/s. assume the initial phase is 0. (include the sign of the value in your answer.) (a) at what position is its velocity 4.4 cm/s? cm (b) what is its velocity when its position is 1.5 cm

a)x=2.86 cm

b)V= 12.99 cm/s

Explanation:

Given that

Amplitude A= 3 cm

Maximum velocity V(max) = 15 cm/s

We know that the  speed in simple harmonic motion given as

x=Displacement from mean position

ω =Angular speed

V(max) = ωA

Now by putting the values

15 =  ω x 3

ω = 5 rad/s

a)

V= 4.4 cm/s

x=2.86 cm

b)

x= 1.5 cm

V= 12.99 cm/s