Vertical cylinder is filled with 0.10 moles of an ideal gas at standard temperature and pressure, and a 1.4-kg piston is initially held above the gas and seals the gas in the cylinder. uniform gravity acts downward. the seal is frictionless. the resulting trapped column of gas is 2.4 meters high. the piston and cylinder are surrounded by air which is also at standard temperature and pressure.

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W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j