A20.0-m-tall hollow aluminum flagpole is equivalent in strength to a solid cylinder 4.00 cm in diameter. a strong wind bends the pole as much as a horizontal 900.0-n force on the top would do. how far to the side does the top of the pole flex?

To solve the problem it is necessary to apply the concepts related to deflection in a metal.

By definition the deflection is given by the equation

Where

Force

A =Area

s = shear modulus

= Original length

To calculate the area we must obtain the radius generated by the deflection, that is to say

r = \frac{D}{2}

Where,

D = Diameter

r = Radius of the aluminum flagpole

Therefore the cross sectional area of the pole is given as

Replacing our values at the previous equation we have that

Therefore the deflection in the pole is 0.57mm

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