A. compute the torque developed by an industrial motor whose ouputis 150kw at an angular speed of 4000 rev/min.
b. a drum with negligible mass and 0.500m in diameter isattached to the motor shaft, and the power output of the motor isused to raise a weight hanging from a rope wrapped around thedrum. how heavy a weight can the motor lift at constantspeed?
c. at what constant speed will the weight rise?

A. τ = 358 N.m

B. m = 73kg

C. V = 209.5 m/s

Explanation:

Let's first convert angular speed to rad/s:

ω = 4000 rev/min * 2π / 60 = 419 rad/s

Since Power is P = τ * ω,

τ = P / ω = 358 N.m

For part B: On the hanging weight:

T - m*g = 0

T = m*g

On the drum:

τ = T*R    Replacing the expression for Tension of the rope:

τ = m*g*R

Solving for m:

m = 73 kg

For part C:

V = ω * R = 209.5 m/s

yup its correct its: c) b b

i just did an experiment like this in my science class. also the answer is yes, it will get separated because they are two opposites meaning if they are opposite they can not attract.

hope this .!