The maximum weight that a rectangular beam can support varies jointly as its width and the square of its height and inversely as its length. if a beam one third 1/3 foot wide, one half 1/2 foot high, and 15 feet long can support 30 tons, find how much a similar beam can support if the beam is one half 1/2 foot wide, one third 1/3 foot high, and 15 feet long?

It's because 3 if it was 10 it wouldn't look right do it goes up to 4d

Answerthe energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.explanationwe define electric potential as the ratio electric potential energy to the charge,    then the following gives us the potential difference,      the formula  may be on your formula sheet.the change in electric potential energy would be the energy that would needed to move it from point a to point b. solving for that, we get    using q = 8.00  × 10⁻¹⁹ c and  δv = 2.00 v, we get    the energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.