The element niobium, which is a metal, is a superconductor (i. e., no electrical resistance) at temperatures below 9 k. however, the superconductivity is destroyed if the magnetic field at the surface of the metal reaches or exceeds 0.10 t. what is the maximum current in a straight, 3.2-mm-diameter superconducting niobium wire?

I=800A

Explanation:

1) Important concepts

Magnetic field represented by B=0.1T, and is defined as"A field  generated when an electric charge via electrons move through the space or in an electrical conductor."

I represent the current (variable os interest)

r represent the radius= 3.2/2 = 1.6mm = 0.0016m

2) Formula to use

For this case we can use the magnetic field due to a wire with current formula, given by:

is a constant

Solving for I from the last formula we got:

And replacing the values given we have:

So the current passing thorugh the wire would be 800 A.

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