Falling raindrops frequently develop electric charges. does this create noticeable forces between the droplets? suppose two 1.8 mg drops each have a charge of +29 pc. the centers of the droplets are at the same height and 0.36 cm apart.

F = 5.83 10⁻¹⁷ N

Explanation:

The electric force is given by

    F = k q₁  q₂ / r²

With Gauss's law electric field flow is equal to the charge inside the Gaussian surface, if we make a spherical surface around each drop, the force independent of small deformations due to air resistance

   q₁ = q₂

   F = 8.99 10⁹ (29 10⁻¹²)² / (0.36 10⁻²)²

   F = 5.83 10⁻¹⁷ N

As the two drops have a charge of the same sign they repel

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.