If a rainstorm drops 5 cm of rain over an area of 13 km2 in the period of 3 hours, what is the momentum (in kg · m/s) of the rain that falls in five seconds? assume the terminal velocity of a raindrop is 10 m/s. (enter the magnitude. the density of water is 1,000 kg/m3.)

To solve the problem it is necessary to apply the concepts related to Conservation of linear Moment.

The expression that defines the linear momentum is expressed as

P=mv

Where,

m=mass

v= velocity

According to our data we have to

v=10m/s

d=0.05m

Volume

t = 3hours=10800s

From the given data we can calculate the volume of rain for 5 seconds

Where,

It is the period of time we want to calculate total rainfall, that is

Through water density we can now calculate the mass that fell during the 5 seconds:

Now applying the prevailing equation given we have to

Therefore the momentum of the rain that falls in five seconds is

the independent variable, or the one that is intentionally manipulated is the speed.

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