The self inductance relates the magnetic flux linkage to the current through the coil. calculate the self inductance l in units of μh. the coil is d = 5 cm long and has a cross-sectional area of a = 3 cm2 and consists of n = 130 turns.

Self inductance,

Explanation:

It is given that,

Length of the coil, l = 5 cm = 0.05 m

Area of cross section of the coil,

Number of turns in the coil, N = 130

The self inductance relates the magnetic flux linkage to the current through the coil and it is given by :

L = 0.000127 Henry

or

So, the self inductance of the coil is 127 microhenry. Hence, this is the required solution.

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft