In a solar system far, far away the sun's intensity is 500 w/m2 for an inner planet located a distance r away. what is the sun's intensity for an outer planet located at a distance 5 r from the sun?

Explanation:

Since intensity is proportional to , being at a distance 5 times farther will make the intensity 25 times smaller, which means that the intensity for an outer planet located at a distance 5 R from the Sun is:

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft