Suppose that a 0.375 m radius 500 turn coil produces an average emf of 12000 v when rotated one-fourth of a revolution in 4.27 ms, starting from its plane being perpendicular to the magnetic field. what is the peak emf generated by this coil, in volts?

epsilon_{peak}= 18833 V

Explanation:

Average emf

⇒

solving this we get

B=0.2320 T

No. of revolutions are 1/4 rev

Δθ=

angular velocity ω =

=

=367.68 rad/sec

The peak emf

putting values we get

solving we get

epsilon_{peak}= 18833 V

Explanation:

Given:

no. of turns in the coil,

area of the coil,

average emf induced,

angle turned by the coil,

time taken to sweep the given angle,

peak emf,

We have the relation between peak emf and average emf as:

.............................(1)

where:

we already know the value:

From eq. (1) we have:

i think if it were me i whould divide 300 dide 15

step-by-step explanation: