Consider a guanabana (5.8 kg) falling from its branch. how much kinetic energy (in joules) does it gain during the time needed for it to drop 6.0 m?

The Kinetic Energy of the guanabana is, K.E = 341.04 J

Explanation:

Given data,

The mass of the guanabana, m = 5.8 kg

The height of the fruit from the ground, h = 6 m

Let the potential energy at the ground be 0

According to the law of conservation of energy, the total energy of a system is conserved.

So, when the guanabana reaches the ground, the P.E is fully converted into K.E

The P.E at height h is

                            P.E = mgh

                                   = 5.8 x 9.8 x 6

                                    = 341.04 J

At ground 6 m drop,

                             P.E = K.E

Therefore, the Kinetic Energy of the guanabana is, K.E = 341.04 J                                                      

the cellphone, they would then know if the killer would have contacted them or always hated them. or if it was a breakup. but if that is not the case, then it would be the clothing. to put in a bullet, it would have to be put in by hands. hands have finger prints which, would have giving you the answer of who done it.

explanation:

as a general rule, scissors have blades less than 6 in (15 cm) long and usually have handles with finger holes of the same size. shears have blades scissors used to cut hair or fabric must be much sharper.