Acannon shoots an artillery shell with a initial velocity of 400 meters/second at an indirect fire angle of 60 on level ground where does it land if friction effects are neglected

14139.19 m

Explanation:

This situation is related to parabolic motion and can be solved using the following equations:

(1)

(2)

Where:

is the horizontal distance (where the artillery shell lands)

is the initial velocity

is the angle

is the time

is the final height

is the initial height

is the acceleration due gravity, always directed downwards

So, let's begin by isolating from (2):

(3)

(4)

Substituting (4) in (1):

(5)

Rewriting (5) and taking into account :

(6)

(7)

Finally:

total distance travelled = 60 miles

total time taken =1.5 hours

average speed = total distance / total time

60 / 1.5

= 40

therefore, average speed = 40 m/h

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