Aparticle is moving along a straight line through a fluid medium such that its speed is measured as v=(2t) m/s, where t is in seconds. if it is released from rest at s=0, determine its positions and acceleration when t=3 s.

2 m/s², 19.62 m

Explanation:

v = Final velocity = 2t

t = Time taken

u = Initial velocity

s = Displacement

a = Acceleration

From the equation of motion

The acceleration of the particle is 2 m/s²

at t = 3 seconds

The position at t = 3 seconds is 19.62 m

what type of charge does it have? negative

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂