1.the sun appears to move across the sky, because the earth spins on its axis. to a person standing on the earth, the sun subtends an angle of θsun = 9.28 × 10−3 rad.2). how much time (in seconds) does it take for the sun to move a distance equal to its own diameter?

This is an astrophysics question and we will use the following formulas to get the time 't' it will take the sun to move a distance equals to it's own diameter 'd'.

Recal:

ω = 2π rads,

Then the earth's angular velocity will be,

ω = (2πrads / (24h * 3600s/h)) = 7.27x10⁻⁵ rad/s

and note that the Angular Acceleration

 ∅= ω*t

9.28x10⁻³rads = 7.27x10⁻⁵rads x t

t = 127 s

Hence, the time (in seconds) it take for the sun to move a distance equal to its own diameter = 127seconds

b

step-by-step explanation: a third of 24 is 8, 8 times 3 is 24 so 8 - 2 would be 6

found in the nucleus

has mass of one amu