A9.00 kg mass is moving to the right with a velocity of 14.0 m/s. a 12.0 kg mass is moving to the left with a velocity of 5.00 m/s. assuming that these two balls have a head on collision and stick together, what will be the final velocity of the combination

3.143 m/s

We are given;

We are required to determine the velocity after collision.

Momentum of A = 9.00 kg × (+14.0 m/s )

                           = 126 kgm/s

Momentum of B = 12.0 kg × (-5.0 m/s)

                            = -60 kgm/s

Thus; Momentum before collision = 126 - 60

                                                         = 66 kgm/s

Momentum after collision = Total mass of the body × Common velocity

                                           = ( 9 kg + 12 kg ) × V

                                           = 21 V kgm/s

But;

Initial momentum = Final momentum

66 kgm/s = 21 V kgm/s

Therefore;

V = 66 ÷ 21

   = 3.143 m/s

   = 3.143 m/s

Therefore, the common velocity of the bodies after collision is 3.143 m/s

the order for strong to weak forces such as

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force

the fundamental forces are those forces that act between to objects or element to make interactions. there are four types of fundamental forces such as strong and weak nuclear forces (due to protons and electrons), electromagnetic force (due to the motion of electrons) and gravitational force (due to orbital movement of the planet). if these forces are arranged on the basis of their maximum strength then the order is

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force