Along, rigid conductor, lying along an x axis, carries a current of 4.99 a in the negative x direction. a magnetic field is present, given by = 3.72 + 8.72 x2, with x in meters and in milliteslas. find (a) the x-component, (b) the y-component, and (c) the z-component of the force on the 1.36 m segment of the conductor that lies between x = 1.41 m and x = 2.77 m.

Answer with Explanation:

We are given that

Current in conductor=I=4.99 A  (-x direction)

Magnetic field=B=

(1mT=)

x(in m) and B (in mT)

Length of conductor is given in negative x- direction

Force on current carrying conductor is given by

Integrating on both sides then we get

 (

a. x- component of force=0

b.y- component of force=0

c.z- component of force=-0.268 N

i think it because equal matrices have equal dimensions, only square matrices can be symmetric. for all indices and . every square diagonal matrix is symmetric, since all off-diagonal elements are zero. in linear algebra, a real symmetric matrix represents a self-adjoint operator over a real inner product space.