An object at rest on a flat, horizontal surface explodes into two fragments, one seven times as massive as the other. the heavier fragment slides 8.10 m before stopping. how far does the lighter fragment slide? part a assume that both fragments have the same coefficient of kinetic friction.

d_1 = 396.9 m

Explanation:

Given data:mass of lighter fragment m

Mass of heavier fragment = 7m

Velocity of lighter fragment  = V1

Velocity of heavier fragment  = V2

As object is rest before explosion occur thus momentum of system is zero

mv1 + 7mv2 = 0

V1 = -7V2

force of Friction on lighter fragment

force of friction on heavier fragment

Deceleration of lighter fragment = a1

we know that force of friction is given as

ma1 = - f1

Deceleration of heavier fragment = a2

7ma2 = -f2

Final velocity of  lighter fragment = V3 = 0 m/s

Final velocity of heavier fragment = V4 = 0 m/s

Distance traveled by lighter fragment prior to rest position is  = d1

Distance traveled by the heavier fragment prior to rest position is  = d2 = 8.10 m

your answer is c! hope this : )

as we know our atmosphere or air have different levels. every level has other gasses, and every gas has another permeability. when the light comes from lower permeability to higher permeability, it changes its direction. so that means that when the light comes from the moon to the earth, it changes it's direction many more times. it basically means that the shape of the light part of the moon is changed on the earth.

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