Aflat coil of wire consisting of 20 turns, each with an area of 50 cm2, is positioned perpendicularly to a uniform magnetic field that increases its magnitude at a constant rate from 2.0 t to 6.0 t in 2.0 s. if the coil has a total resistance of 0.40 ω, what is the magnitude of the induced current?
a. 0.70 a
b. 0.60 a
c. 0.50 a
d. 0.80 a
e. 0.20 a

Induced current, I = 0.5 A

Explanation:

It is given that,

number of turns, N = 20

Area of wire,

Initial magnetic field,

Final magnetic field,

Time taken, t = 2 s

Resistance of the coil, R = 0.4 ohms

We know that due to change in magnetic field and emf will be induced in the coil. Its formula is given by :

Where

Let I is the induced current in the wire. It can be calculated using Ohm's law as :

I = 0.5 A

So, the magnitude of the induced current in the coil is 0.5 A. Hence, this is the required solution.

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explanation: