The surfaces between a 7 kg block, the 23 kg wedge and between the 23 kg wedge and the horizontal plane are smooth (without friction). the acceleration of gravity is 9.8 m/s 2 . a block is released on the inclined plane (top side of the wedge). 7 kg 29◦ 23 kg 9 f .8 m /s^2. what is the force f which must be exerted on the 23 kg block in order that the 7 kg block does not move up or down the plane? answer in units of n.

1.)the isotope cobalt-60 has a nuclear mass of 59.933820 u calculate the mass defect of cobalt-60 using the following information. mass of proton: 1.007825 u mass of neutron: 1.008665 u 1 u = 931.5 mev 2.)the isotope cobalt-60 has a nuclear mass of 59.933820 u calculate the binding energy of cobalt-60 using the following information. mass of proton: 1.007825 u mass of neutron: 1.008665 u 1 u = 931.5 mev 3.)the isotope cobalt-60 has a nuclear mass of 59.933820 u calculate the binding energy per nucleon of cobalt-60 using the following information. mass of proton: 1.007825 u mass of neutron: 1.008665 u 1 u = 931.5 mev

More solar radiation is absorbed by earth’s surface than by

What happens when you slowly pulled the carboard?