If the barometeric pressure was 0.97 atm when the mercury level in an open-end manometer connected to a flask of gas was 191 mmhg higher on the side open to the atmosphere than on the flask side, what was the pressure of the gas in the flask in torr? enter your answer with two decimal places and no units. (hint: sketch the apparatus.)

The pressure of the gas in the flask is 72.79kPa

Explanation:

To solve the problem it is necessary to take into account the concepts related to pressure due to the weight of a fluid.

The equation that represents this pressure is given by,

Thus the change in pressure due to the weight of a fluid is given by

Where,

P = Pressure

h = height/depth

g = Gravity acceleration

= Density of the fluid

From the values previous given, we have

Density of Mercury:

Barometric Pressure: 0.97atm = 737.19 mmHg

Reading of Open Manometer: 191mmHg

Then we have:

Therefore the pressure of the gas in the flask is 72.79kPa

hi there!

your question asks at which segment does freezing occur.

since we're talking about water, the freezing point of water will be 32 degrees fahrenheit or below.

hope this ! ~

answer: at 24 february, 2014 the population gets twice of its initial population.

explanation:

since we have given that

the population for alpha city, t years after january 1, 2004 is given as

first we find out the initial population, i.e. t=0,

so, our quadratic equation becomes,

according to question, we have said that if the population has twice its initial population, then it becomes

so, time taken to reach this above mentioned population is given by

now, we know that time can't be negative so, we take t=9.149 years.

hence, at 24 february, 2014 the population gets twice of its initial population.